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0=16x^2+12x+10
We move all terms to the left:
0-(16x^2+12x+10)=0
We add all the numbers together, and all the variables
-(16x^2+12x+10)=0
We get rid of parentheses
-16x^2-12x-10=0
a = -16; b = -12; c = -10;
Δ = b2-4ac
Δ = -122-4·(-16)·(-10)
Δ = -496
Delta is less than zero, so there is no solution for the equation
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